Sort a list based on an another list

Sorting a list based on another list sorts the elements of the first list by the value of the element in the same position in the second list.

For example, sorting ["new", "hold", "close"]  based on ['hold', 'close', 'withdraw', 'new', 'deposit', 'rollin', 'rebalance', 'switch']  results in ["hold", "close", "new"].

Call sorted on your list passing in argument the function that will perform the sorting.

Let's define the base list used as a reference for the sorting:

<:let base_list = ['hold', 'close', 'withdraw', 'new', 'deposit', 'rollin', 'rebalance', 'switch']:>

<:let my_list = ["new", "hold", "close"]:>

<:let my_sorted_list = sorted(my_list , key=lambda x: base_list.index(x) if x in base_list else x):>

The function returns the position of each element of my_list from base_list in order to perform the sorting